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Aptitude Topics
 Height and Distance
 Simple Interest
 Profit and Loss
 Percentage
 Calender
 Average
 Volume and Surface Area
 Numbers
 Problems on H.C.F and L.C.M
 Simplification
 Surds and Indices
 Chain Rule
 Boat and Streams
 Logarithm
 Stocks and Shares
 True Discount
 Odd Man Out and Series
 Time and Distance
 Time and Work
 Compound Interest
 Partnership
 Problems on Ages
 Clock
 Area
 Permutation and Combination
 Problems on Numbers
 Decimal Fraction
 Square Root and Cube Root
 Ratio and Proportion
 Pipes and Cistern
 Alligation or Mixture
 Races and Games
 Probability
 Banker's Discount
Average
Answer: Option A
Explanation:
Required run rate =  282  (3.2 x 10)  =  250  = 6.25  
40  40 
Answer: Option B
Explanation:
Required average 







Answer: Option A
Explanation:
Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.
Required sale = Rs. [ (6500 x 6)  34009 ]
= Rs. (39000  34009)
= Rs. 4991.
Answer: Option D
Explanation:
Average of 20 numbers = 0.
Sum of 20 numbers (0 x 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (a).
Answer: Option C
Explanation:
Total weight increased = (8 x 2.5) kg = 20 kg.
Weight of new person = (65 + 20) kg = 85 kg.
The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team? 


Answer: Option A
Explanation:
Let the average age of the whole team by x years.
11x  (26 + 29) = 9(x 1)
11x  9x = 46
2x = 46
x = 23.
Answer: Option B
Explanation:
Let P, Q and R represent their respective monthly incomes. Then, we have:
P + Q = (5050 x 2) = 10100 .... (i)
Q + R = (6250 x 2) = 12500 .... (ii)
P + R = (5200 x 2) = 10400 .... (iii)
Adding (i), (ii) and (iii), we get: 2(P + Q + R) = 33000 or P + Q + R = 16500 .... (iv)
Subtracting (ii) from (iv), we get P = 4000.
P's monthly income = Rs. 4000.
Answer: Option B
Explanation:
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
Husband's present age = (90  50) years = 40 years.
A car owner buys petrol at Rs.75, Rs. 80 and Rs. 85 per liter for three successive years. What approximately is the average cost per liter of petrol if he spends Rs. 40000 each year?
A. Rs. 79.8
B. Rs. 80
C. Rs. 85
D. Rs. 90
Answer: Option A
Explanation:
Total quantity of petrol consumed in 3 years 





Total amount spent = Rs. (3 x 40000) = Rs. 120000.
Average cost = Rs.  120000 x 51  = Rs.  6120  = Rs. 7.98  
767000  767 
In Arun's opinion, his weight is greater than 65 kg but less than 72 kg. His brother doest not agree with Arun and he thinks that Arun's weight is greater than 60 kg but less than 70 kg. His mother's view is that his weight cannot be greater than 68 kg. If all are them are correct in their estimation, what is the average of different probable weights of Arun? 


Answer: Option A
Explanation:
Let Arun's weight by X kg.
According to Arun, 65 < X < 72
According to Arun's brother, 60 < X < 70.
According to Arun's mother, X <= 68
The values satisfying all the above conditions are 66, 67 and 68.
Required average =  66 + 67 + 68  =  201  = 67 kg.  
3  3 
Answer: Option D
Explanation:
Let A, B, C represent their respective weights. Then, we have:
A + B + C = (45 x 3) = 135 .... (i)
A + B = (40 x 2) = 80 .... (ii)
B + C = (43 x 2) = 86 ....(iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv)
Subtracting (i) from (iv), we get : B = 31.
B's weight = 31 kg.
Answer: Option C
Explanation:
Required average 






= 48.55 
Answer: Option D
Explanation:
Since the month begins with a Sunday, to there will be five Sundays in the month.
Required average 




= 285 
Answer: Option B
Explanation:
Required average 






= 54.68 
Answer: Option C
Explanation:
Let there be x pupils in the class.
Total increase in marks =  x x  1  =  x  
2  2 
x  = (83  63)  x  = 20 x= 40.  
2  2 