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Percentage
Answer: Option C
Explanation:
Let their marks be (x + 9) and x.
Then, x + 9 = | 56 | (x + 9 + x) |
100 |
25(x + 9) = 14(2x + 9)
3x = 99
x = 33
So, their marks are 42 and 33.
Answer: Option D
Explanation:
Suppose originally he had x apples.
Then, (100 - 40)% of x = 420.
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60 | x x = 420 |
100 |
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![]() |
420 x 100 | ![]() |
60 |
Answer: Option C
Explanation:
Clearly, the numbers which have 1 or 9 in the unit's digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.
Number of such number =14
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![]() |
14 | x 100 | ![]() |
70 |
Answer: Option E
Explanation:
x% of y = | ![]() |
x | x y | ![]() |
= | ![]() |
y | x x | ![]() |
= y% of x |
100 | 100 |
A = B.
Answer: Option A
Explanation:
20% of a = b ![]() |
20 | a = b. |
100 |
![]() |
![]() |
b | x 20 | ![]() |
= | ![]() |
20 | a x | 1 | x 20 | ![]() |
= | 4 | a = 4% of a. |
100 | 100 | 100 | 100 |
Answer: Option E
Explanation:
Let the number of students be x. Then,
Number of students above 8 years of age = (100 - 20)% of x = 80% of x.
![]() |
2 | of 48 |
3 |
![]() |
80 | x = 80 |
100 |
x = 100.
Answer: Option D
Explanation:
5% of A + 4% of B = | 2 | (6% of A + 8% of B) |
3 |
![]() |
5 | A + | 4 | B | = | 2 | ![]() |
6 | A + | 8 | B | ![]() |
100 | 100 | 3 | 100 | 100 |
![]() |
1 | A + | 1 | B | = | 1 | A + | 4 | B |
20 | 25 | 25 | 75 |
![]() |
![]() |
1 | - | 1 | ![]() |
![]() |
4 | - | 1 | ![]() |
20 | 25 | 75 | 25 |
![]() |
1 | A = | 1 | B |
100 | 75 |
A | = | 100 | = | 4 | . |
B | 75 | 3 |
Required ratio = 4 : 3
Answer: Option D
Explanation:
Let the number be x.
Then, error = | 5 | x - | 3 | x = | 16 | x. |
3 | 5 | 15 |
Error% = | ![]() |
16x | x | 3 | x 100 | ![]() |
15 | 5x |
Answer: Option A
Explanation:
Number of valid votes = 80% of 7500 = 6000.
Valid votes polled by other candidate = 45% of 6000
= | ![]() |
45 | x 6000 | ![]() |
= 2700. |
100 |
Answer: Option A
Explanation:
Total number of votes polled = (1136 + 7636 + 11628) = 20400.
![]() |
![]() |
11628 | x 100 | ![]() |
20400 |
Answer: Option B
Explanation:
Let the sum paid to Y per week be Rs. z.
Then, z + 120% of z = 550.
![]() |
120 | z = 550 |
100 |
![]() |
11 | z = 550 |
5 |
![]() |
![]() |
550 x 5 | ![]() |
11 |
Answer: Option C
Explanation:
Let the amount taxable purchases be Rs. x.
Then, 6% of x = | 30 |
100 |
![]() |
![]() |
30 | x | 100 | ![]() |
100 | 6 |
Cost of tax free items = Rs. [25 - (5 + 0.30)] = Rs. 19.70
Answer: Option A
Explanation:
Rebate = 6% of Rs. 6650 = Rs. | ![]() |
6 | x 6650 | ![]() |
= Rs. 399. |
100 |
Sales tax = 10% of Rs. (6650 - 399) = Rs. | ![]() |
10 | x 6251 | ![]() |
= Rs. 625.10 |
100 |
Final amount = Rs. (6251 + 625.10) = Rs. 6876.10
Answer: Option B
Explanation:
Increase in 10 years = (262500 - 175000) = 87500.
Increase% = | ![]() |
87500 | x 100 | ![]() |
175000 |
![]() |
![]() |
50 | ![]() |
10 |