- Home
- Aptitude Tests
- Simple Interest
Aptitude Topics
- Height and Distance
- Simple Interest
- Profit and Loss
- Percentage
- Calender
- Average
- Volume and Surface Area
- Numbers
- Problems on H.C.F and L.C.M
- Simplification
- Surds and Indices
- Chain Rule
- Boat and Streams
- Logarithm
- Stocks and Shares
- True Discount
- Odd Man Out and Series
- Time and Distance
- Time and Work
- Compound Interest
- Partnership
- Problems on Ages
- Clock
- Area
- Permutation and Combination
- Problems on Numbers
- Decimal Fraction
- Square Root and Cube Root
- Ratio and Proportion
- Pipes and Cistern
- Alligation or Mixture
- Races and Games
- Probability
- Banker's Discount
Simple Interest
Answer: Option C
Explanation:
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 - 117) = Rs. 698.
Answer: Option A
Explanation:
Let the sum invested in Scheme A be Rs. x and that in Scheme B be Rs. (13900 - x).
Then, | ![]() |
x x 14 x 2 | ![]() |
+ | ![]() |
(13900 - x) x 11 x 2 | ![]() |
= 3508 |
100 | 100 |
28x - 22x = 350800 - (13900 x 22)
6x = 45000
x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Answer: Option D
Explanation:
Principal |
|
|||||
|
||||||
= Rs. 8925. |
Answer: Option B
Explanation:
Time = | ![]() |
100 x 81 | ![]() |
= 4 years. |
450 x 4.5 |
Answer: Option B
Explanation:
Let rate = R% and time = R years.
Then, | ![]() |
1200 x R x R | ![]() |
= 432 |
100 |
12R2 = 432
R2 = 36
R = 6.
Answer: Option D
Explanation:
S.I. = Rs. (15500 - 12500) = Rs. 3000.
Rate = | ![]() |
100 x 3000 | ![]() |
= 6% |
12500 x 4 |
Answer: Option B
Explanation:
Let the sum be Rs. 100. Then,
S.I. for first 6 months = Rs. | ![]() |
100 x 10 x 1 | ![]() |
= Rs. 5 |
100 x 2 |
S.I. for last 6 months = Rs. | ![]() |
105 x 10 x 1 | ![]() |
= Rs. 5.25 |
100 x 2 |
So, amount at the end of 1 year = Rs. (100 + 5 + 5.25) = Rs. 110.25
Effective rate = (110.25 - 100) = 10.25%
Answer: Option D
Explanation:
Let the rate be R% p.a.
Then, | ![]() |
5000 x R x 2 | ![]() |
+ | ![]() |
3000 x R x 4 | ![]() |
= 2200. |
100 | 100 |
100R + 120R = 2200
![]() |
![]() |
2200 | ![]() |
= 10. |
220 |
Rate = 10%.
A sum of Rs. 725 is lent in the beginning of a year at a certain rate of interest. After 8 months, a sum of Rs. 362.50 more is lent but at the rate twice the former. At the end of the year, Rs. 33.50 is earned as interest from both the loans. What was the original rate of interest? |
||||||||||
|
Answer: Option E
Explanation:
Let the original rate be R%. Then, new rate = (2R)%.
Note:
Here, original rate is for 1 year(s); the new rate is for only 4 months i.e. year(s).
![]() |
![]() |
725 x R x 1 | ![]() |
+ | ![]() |
362.50 x 2R x 1 | ![]() |
= 33.50 |
100 | 100 x 3 |
(2175 + 725) R = 33.50 x 100 x 3
(2175 + 725) R = 10050
(2900)R = 10050
![]() |
10050 | = 3.46 |
2900 |
Original rate = 3.46%
Answer: Option C
Explanation:
Principal = Rs. | ![]() |
100 x 5400 | ![]() |
= Rs. 15000. |
12 x 3 |
Answer: Option C
Explanation:
S.I. for 3 years = Rs. (12005 - 9800) = Rs. 2205.
S.I. for 5 years = Rs. | ![]() |
2205 | x 5 | ![]() |
= Rs. 3675 |
3 |
Principal = Rs. (9800 - 3675) = Rs. 6125.
Hence, rate = | ![]() |
100 x 3675 | ![]() |
= 12% |
6125 x 5 |
Answer: Option C
Explanation:
Let the principal be P and rate of interest be R%.
![]() |
|
= | 6PR | = | 6 | = 2 : 3. | ||||
|
9PR | 9 |
Answer: Option D
Explanation:
We need to know the S.I., principal and time to find the rate.
Since the principal is not given, so data is inadequate.
Answer: Option A
Explanation:
Gain in 2 years |
|
||||||||||||||||
= Rs. (625 - 400) | |||||||||||||||||
= Rs. 225. |
![]() |
![]() |
225 | ![]() |
= Rs. 112.50 |
2 |